4sheets Jewelry Pattern Nail Art Sticker

4sheets Jewelry Pattern Nail Art Sticker


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Does the C# spec guarantee an implementation of the IEnumerable interface?

Does C# guarantee that IEnumerable exists and is implemented in such a way that is consistent with this contract in the C# specification?
I think the implementation for IEnumerable isn’t defined this way so it’s a guess.
The specification for IEnumerator provides more details for implementations of an enumerator than I could find for IEnumerable implementations. Maybe I’m missing something here.
From the C# specification:

[T]he class IEnumerable is an abstract (generic) interface that contains a single method named GetEnumerator, and an abstract base class named System.Collections.IEnumerable which is intended to be the base class of all generic interfaces that implement a non-generic IEnumerable interface and which inherits from System.Collections.Generic.IEnumerable. In addition, it has a type parameter, T.

And from the IEnumerable and IEnumerator abstract base classes:

[T]he class IEnumerable is an abstract (generic) interface that contains a single method named GetEnumerator, and an abstract base class named System.Collections.IEnumerator that is intended to be the base class of all non-generic interfaces that implement a non-generic IEnumerable interface.

A:

IEnumerable is basically a wrapper around IEnumerable and is just an abstract class that defines these two methods:
IEnumerable.GetEnumerator()

IEnumerator.Current

And IEnumerable represents all implementations of IEnumerable that accept the type parameter T:

IEnumerable implements the IEnumerable interface. T represents the type of objects in a sequence.

It’s guaranteed that all implementations of IEnumerable<

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