Random Allover Print Halter Triangle Bikini Top & Flounce Sleeve Cover Up

Random Allover Print Halter Triangle Bikini Top & Flounce Sleeve Cover Up

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Looking for a new bikini top that will make a statement? Check out our random allover print halter triangle bikini top! This top is sure to turn heads with its unique print and flattering silhouette. Pair it with our flounce sleeve cover up for the perfect beach day look.

$49.90

$32.50

Pantie Plunge Bikini Panties

Finding a unique pair of trendy and fashionable panties is easy these days. If you are looking to wear cute and comfortable panties that pair perfectly with a pair of jean or shorts, then make sure you check out our sexy plunge panties! We have a sweet variety of different prints and styles so you are sure to find the perfect pair.Q:

Excel: how to find an exact match in a column between a reference, a list of cells, or a range of cells?

Suppose I have a list of items, and a list of their unique identifiers — in this case, the first column of the item’s data is the unique identifier. I’d like to have a list of the unique identifiers in another column.
This seems like it should be ridiculously easy: I get the reference, or the list of values, or the range of cells:
=IFERROR(INDEX($A$1:$A$6,MATCH(1,–,$B$1:$B$6,0)),””)

that works if I know the rows I’m looking at are the first six, so something that works if I know that my list of values is in the range A1-A6, for example. Yet when I test it I can’t get it to work, even though it says the formula is correct…
What am I doing wrong? This isn’t even super-easy in VBA, either.
My end goal is to do a similar lookup using a lookup table in case the list is a huge one. I haven’t been able to find any examples to try in VBA yet, but that’s also on my list of things to study. I’ll need to go that route if I have no other solution.

Update with working solution
Thanks to @Jakob Tande’s answer, this formula worked perfectly:
=IFERROR(IF(COUNTIF($F$2:$F$9,D2)>0,INDEX($F$2:$F$9,MATCH($D2,$F$2:$F$9)),””))

(I had the ranges all the way across, but it was wrong.)
I’m going to add in what @K

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